“No Ordinary Genius” by Richard Feynman and Christopher Sykes

This book complements Feynman’s autobiography “Surely You’re Joking, Mr. Feynman” and sequel “What Do you Care What Other People Think” very well. It includes interviews from Feynman’s colleagues, family and friends, as well as himself, and gives the reader a more complete picture of the man and a life fully lived.

Genius

“Feynman’s great secret in solving the problem of quantum electrodynamics was that he developed this way to do it graphically, rather than by writing down formulas. As you know, this led to the Feynman diagrams which everybody is using now for any kind of calculation in field theory. The great power of Feynman’s diagrams is that they combine many steps of the older calculations in one. In the time before Feynman, we would do it all longhand on paper, in algebra, and we would have to consider electrons and positrons separately. This was a very lengthy affair. Feynman was able to combine this, so that only one diagram needed to be calculated. That’s the genius!’
— Hans Bethe, Nobel laureate in physics

Dying of Cancer

He said something which I wish I could remember exactly. It was to the effect, “Yeah, it bugs me, but it doesn’t bug me as much as you think it would, because I feel like I’ve told enough stories to other people, and enough of me is inside their minds. I’ve kind of spread me around all over the place. So I’m probably not going to go away completely when I’m dead!” That’s closest to any sort of philosophy or religion I ever got out of Richard.
— Danny Hillis, computer scientist

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One thought on ““No Ordinary Genius” by Richard Feynman and Christopher Sykes

  1. V1143Cgyni Binary Stars Apsidal motion Puzzle solution

    The motion puzzle that Einstein MIT Harvard Cal-Tech NASA and all others could not solve.

    Introduction: For 350 years Physicists Astronomers and Mathematicians missed Kepler’s time dependent equation that changed Newton’s equation into a time dependent Newton’s equation and together these two equations combine classical mechanics and quantum mechanics into one mechanics explains “relativistic” effects as the difference between time dependent measurements and time independent measurements of moving objects and solve all motion in all of Mechanics posted on Smithsonian NASA website SAO/NASA that Einstein and all 100,000 space-time “physicists” could not solve by space-time physics or any published physics.

    All there is in the Universe is objects of mass m moving in space (x, y, z) at a location
    r = r (x, y, z). The state of any object in the Universe can be expressed as the product

    S = m r; State = mass x location:

    P = d S/d t = m (d r/dt) + (dm/dt) r = Total moment
    = change of location + change of mass
    = m v + m’ r; v = velocity = d r/d t; m’ = mass change rate

    F = d P/d t = d²S/dt² = Total force
    = m(d²r/dt²) +2(dm/dt)(d r/d t) + (d²m/dt²)r
    = mγ + 2m’v +m”r; γ = acceleration; m” = mass acceleration rate

    In polar coordinates system

    r = r r(1) ;v = r’ r(1) + r θ’ θ(1) ; γ = (r” – rθ’²)r(1) + (2r’θ’ + rθ”)θ(1)
    Proof:
    r = r [cosθ î + sinθĴ] = r r (1); r (1) = cosθ î + sinθ Ĵ
    v = d r/d t = r’ r (1) + r d[r (1)]/d t = r’ r (1) + r θ'[- sinθ î + cos θĴ] = r’ r (1) + r θ’ θ (1)

    θ (1) = -sinθ î +cosθ Ĵ; r(1) = cosθî + sinθĴ

    d [θ (1)]/d t= θ’ [- cosθî – sinθĴ= – θ’ r (1)
    d [r (1)]/d t = θ’ [ -sinθ’î + cosθ]Ĵ = θ’ θ(1)

    γ = d [r’r(1) + r θ’ θ (1)] /d t = r” r(1) + r’ d[r(1)]/d t + r’ θ’ r(1) + r θ” r(1) +r θ’ d[θ(1)]/d t

    γ = (r” – rθ’²) r(1) + (2r’θ’ + r θ”) θ(1)

    F = m[(r”-rθ’²)r(1) + (2r’θ’ + rθ”)θ(1)] + 2m'[r’r(1) + rθ’θ(1)] + (m”r) r(1)

    = [d²(mr)/dt² – (mr)θ’²]r(1) + (1/mr)[d(m²r²θ’)/dt]θ(1) = [-GmM/r²]r(1)

    d²(mr)/dt² – (mr)θ’² = -GmM/r² Newton’s Gravitational Equation (1)
    d(m²r²θ’)/dt = 0 Central force law (2)

    (2) : d(m²r²θ’)/d t = 0 m²r²θ’ = [m²(θ,0)φ²(0,t)][ r²(θ,0)ψ²(0,t)][θ'(θ, t)]
    = [m²(θ,t)][r²(θ,t)][θ'(θ,t)]
    = [m²(θ,0)][r²(θ,0)][θ'(θ,0)]
    = [m²(θ,0)]h(θ,0);h(θ,0)=[r²(θ,0)][θ'(θ,0)]
    = H (0, 0) = m² (0, 0) h (0, 0)
    = m² (0, 0) r² (0, 0) θ'(0, 0)
    m = m (θ, 0) φ (0, t) = m (θ, 0) Exp [λ (m) + ì ω (m)] t; Exp = Exponential
    φ (0, t) = Exp [ λ (m) + ỉ ω (m)]t

    r = r(θ,0) ψ(0, t) = r(θ,0) Exp [λ(r) + ì ω(r)]t
    ψ(0, t) = Exp [λ(r) + ỉ ω (r)]t

    θ'(θ, t) = {H(0, 0)/[m²(θ,0) r(θ,0)]}Exp{-2{[λ(m) + λ(r)]t + ì [ω(m) + ω(r)]t}} ——I
    Kepler’s time dependent equation that Physicists Astrophysicists and Mathematicians missed for 350 years that is going to demolish Einstein’s space-jail of time

    θ'(0,t) = θ'(0,0) Exp{-2{[λ(m) + λ(r)]t + ỉ[ω(m) + ω(r)]t}}

    (1): d² (m r)/dt² – (m r) θ’² = -GmM/r² = -Gm³M/m²r²

    d² (m r)/dt² – (m r) θ’² = -Gm³ (θ, 0) φ³ (0, t) M/ (m²r²)

    Let m r =1/u

    d (m r)/d t = -u’/u² = -(1/u²)(θ’)d u/d θ = (- θ’/u²)d u/d θ = -H d u/d θ
    d²(m r)/dt² = -Hθ’d²u/dθ² = – Hu²[d²u/dθ²]

    -Hu² [d²u/dθ²] -(1/u)(Hu²)² = -Gm³(θ,0)φ³(0,t)Mu²
    [d²u/ dθ²] + u = Gm³(θ,0)φ³(0,t)M/H²

    t = 0; φ³ (0, 0) = 1
    u = Gm³(θ,0)M/H² + Acosθ =Gm(θ,0)M(θ,0)/h²(θ,0)

    mr = 1/u = 1/[Gm(θ,0)M(θ,0)/h(θ,0) + Acosθ]
    = [h²/Gm(θ,0)M(θ,0)]/{1 + [Ah²/Gm(θ,0)M(θ,0)][cosθ]}

    = [h²/Gm(θ,0)M(θ,0)]/(1 + εcosθ)
    mr = [a(1-ε²)/(1+εcosθ)]m(θ,0)

    r(θ,0) = [a(1-ε²)/(1+εcosθ)] m r = m(θ, t) r(θ, t)
    = m(θ,0)φ(0,t)r(θ,0)ψ(0,t)

    r(θ,t) = [a(1-ε²)/(1+εcosθ)]{Exp[λ(r)+ω(r)]t} Newton’s time dependent Equation ——–II

    If λ (m) ≈ 0 fixed mass and λ(r) ≈ 0 fixed orbit; then

    θ'(0,t) = θ'(0,0) Exp{-2ì[ω(m) + ω(r)]t}

    r(θ, t) = r(θ,0) r(0,t) = [a(1-ε²)/(1+εcosθ)] Exp[i ω (r)t]

    m = m(θ,0) Exp[i ω(m)t] = m(0,0) Exp [ỉ ω(m) t] ; m(0,0)

    θ'(0,t) = θ'(0, 0) Exp {-2ì[ω(m) + ω(r)]t}

    θ'(0,0)=h(0,0)/r²(0,0)=2πab/Ta²(1-ε)²

    = 2πa² [√ (1-ε²)]/T a² (1-ε) ²; θ'(0, 0) = 2π [√ (1-ε²)]/T (1-ε) ²

    θ'(0,t) = {2π[√(1-ε²)]/T(1-ε)²}Exp{-2[ω(m) + ω(r)]t

    θ'(0,t) = {2π[√(1-ε²)]/(1-ε)²}{cos 2[ω(m) + ω(r)]t – ỉ sin 2[ω(m) + ω(r)]t}

    θ'(0,t) = θ'(0,0) {1- 2sin² [ω(m) + ω(r)]t – ỉ 2isin [ω(m) + ω(r)]t cos [ω(m) + ω(r)]t}

    θ'(0,t) = θ'(0,0){1 – 2[sin ω(m)t cos ω(r)t + cos ω(m) sin ω(r) t]²}

    – 2ỉ θ'(0, 0) sin [ω (m) + ω(r)] t cos [ω (m) + ω(r)] t

    Δ θ (0, t) = Real Δ θ (0, t) + Imaginary Δ θ (0.t)

    Real Δ θ (0, t) = θ'(0, 0) {1 – 2[sin ω (m) t cos ω(r) t + cos ω (m)t sin ω(r)t]²}

    W(ob) = Real Δ θ (0, t) – θ'(0, 0) = – 2 θ'(0, 0){(v°/c)√ [1-(v*/c) ²] + (v*/c)√ [1- (v°/c) ²]}²

    v ° = spin velocity; v* = orbital velocity; v°/c = sin ω (m)t; v*/c = cos ω (r) t

    v°/c << 1; (v°/c)² ≈ 0; v*/c << 1; (v*/c)² ≈ 0

    W (ob) = – 2[2π √ (1-ε²)/T (1-ε) ²] [(v° + v*)/c] ²

    W (ob) = (- 4π /T) {[√ (1-ε²)]/ (1-ε) ²} [(v° + v*)/c] ² radians
    W (ob) = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} [(v° + v*)/c] ² degrees; Multiplication by 180/π

    W° (ob) = (-720×36526/T) {[√ (1-ε²)]/ (1-ε) ²} [(v°+ v*)/c] ² degrees/100 years

    W” (ob) = (-720x26526x3600/T) {[√ (1-ε²)]/ (1-ε) ²} [(v° + v*)/c] ² seconds /100 years

    The circumference of an ellipse: 2πa (1 – ε²/4 + 3/16(ε²)²- –.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4)
    v (m) = √ [GM²/ (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system
    v (M) = √ [Gm² / (m + M)a(1-ε²/4)] ≈ 0; m<<M

    Application 1: Advance of Perihelion of mercury.

    G=6.673×10^-11; M=2×10^30kg; m=.32×10^24kg; ε = 0.206; T=88days
    c = 299792.458 km/sec; a = 58.2km/sec; 1-ε²/4 = 0.989391
    ρ (m) = 0.696×10^9m; ρ(m)=2.44×10^6m; T(sun) = 25days
    v° (M) = 2km/sec ; v° = 2meters/sec
    v *= v(m) = √ [GM/a (1-ε²/4)]; v(M) = √[Gm²/(m + M)a(1-ε²)] ≈ 0
    v°(m) = 2m/sec (Mercury) v°(M)= 2km/sec(sun)
    Calculations yields: v = v* + v° =48.14km/sec (mercury); [√ (1- ε²)] (1-ε) ² = 1.552
    W” (ob) = (-720x36526x3600/T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ²
    W” (ob) = ( -720x36526x3600/88 ) x (1.552) (48.14/299792)² = 43.0”/century

    V1143Cgyni Apsidal Motion Solution

    W° (ob) = (-720×36526/T) {[√ (1-ε²)]/ (1-ε) ²} [(v°+ v*)/c] ² degrees/100 years

    v° = -v°(m) + v°(M)
    v* = 2v(cm) + σ
    v°(m) = spin velocity of primary
    v°(M) = spin velocity of secondary
    v(cm) = [m v(m) + M v(M)]/(m + M) center of mass velocity
    σ = √ {{[v(m) – v(cm)]² + [v(M) – v(cm)]²}/2} = standard deviation
    W° = 3.36°/century as reported in many articles

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